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10x^2-29x-10=0
a = 10; b = -29; c = -10;
Δ = b2-4ac
Δ = -292-4·10·(-10)
Δ = 1241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{1241}}{2*10}=\frac{29-\sqrt{1241}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{1241}}{2*10}=\frac{29+\sqrt{1241}}{20} $
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